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If the coefficient of friction is 0.2 find the least horizontal force required to prevent the block slipping. 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CWBMouseStroke!80 CWBMouseStroke"80 CWBMouseStroke#8k2 CWBMouseStroke$83 CWBMouseStroke%84 CWBMouseStroke& 8 8       CWBMouseStroke'@89 6 "####"!  !$%')*++,,,,,,,,-./012345567899::::CWBMouseStroke( 8= CWBMouseStroke)?5G8?> @@@??>==<<=>?@AACWBMouseStroke*@9P8@? @CFJJJCWBMouseStroke+zs8zF zzzzzz{|~CWBMouseStroke,8H CWBMouseStroke-8I CWBMouseStroke.8K CWBMouseStrokeZ\9DCWBMouseStroke184P CWBMouseStroke4 8"S CWBMouseStroke58ZT  CWBMouseStroke6@8EU F !"##"! !#&)+-.///..--../123467899::::::CWBMouseStroke7 8Y CWBMouseStrokeK CWBMouseStrokeUVX CWBMouseStrokefh CWBMouseStrokegh Gx  8S8V\8_hCPageCWBTextiU9U9{<BIf a block of weight 100 N rests on a rough plane inclined at an angle A to the horizontal, where Tan A = 0.75, and the coefficient of friction = 0.4 find the least force parallel to the plane required to prevent the block slipping. "ArialY"GCPageCWBMouseStrokejbG[lMbG=bGbGcGcGcGdFdFdFeEfEgDhDjCkBmAo@r?u>x<|:8631.+($!  (4AM[hu{wsssCWBMouseStrokekeM_D2_eM]fNfNfNfMfMgMgMgMhMhMiMjMjMkMlMnMoMpMrMtMuMwMyM{M~NMMMMMMMMMMMMLLLLLLLLLLLLLKKKKKKK KLLL%L,M4M;MBNJNQOYOaOiOqPyPPPPPQQQQQRRSTVWX#Y,Y,Y,YCWBMouseStrokel$?o$7%%%%%&&&''(()**+,,-.//011233455667777888888888889999988CWBMouseStrokem%qo%X^&')+,.1369<?BFIMPTWZ^acfhjl~n}p|q{r{sztzuzvyvywywyxxxxxxxxxxxxxxwxwxwxwxwxwxwxwxwywywzw{w|w}x~xyyyzzz{{||}~CWBMouseStroken71o7A+88888889::;<>?ACEHJMPSVY\_cfimpswz}CWBMouseStrokepE%KsEo?7EEEEEEDDDCBA@?=<:975421/..-,,,--./01345789:;<==>>>>>>>>CWBMouseStrokeq>8Js>H?????????@@@AABBCCCDDDDDDCCCCWBMouseStroker>7Es>iM>>>????>>>>>>>>>>>>CWBMouseStroketaZk7y aKabbbbbbbbbbbbbbbbbbaaaaaaaabbbbbbbbcccccccdd d dddddddd d#d%d'd(d*e+e-e.e/d/d0d1d1d1d1d1d1d1d1d0d0d0CWBMouseStrokeu] Vt:y ] G(^ ^ ^ ] ] ] ] ] ] ]!^"^#^$^%_'_(`*`+a-b.b0c1c2c3d4d4d4e4e3f3g2h0i.j,k*l(m&n$n"n"CWBMouseStrokev@8Gy @@@AAAAA@@@??? ? ? ? ? ? CWBMouseStrokewHAT y HHHHHHHHIIJKLMNNNNMLKJIIIICWBMouseStrokexTL` y TTTSSSTTUVWXYZZYXWUTSSSCWBMouseStrokez](_d~ ]{%^]]\\[ZZYXWVTSRPOMLJHGECA?=~;{9x7u5r3o2l1i/f/f/fCWBMouseStroke{+j!]Cw~ +j,j+k+l*m*o)p)q)q(q(q(q(p)n)l*k*i*g*f+e+e,d,e.e0f2g4g7h:h=g=g=gCWBMouseStroke|R Kq~ RRRSTVXZ]adfhjkkkCWBMouseStroke}S H$j~ SSQPOOOPQRSTUVWXYZ[\\]^_`abcddddCWBMouseStroke^W ^_^^^__``bcegjmptw{CWBMouseStroke !CWBMouseStroke_ ,9~|zxvtrpnlkihgffffgijlnpqqrqqpnmkigfffghjlmnooooCWBMouseStroke^Xw ^b __`bdgjmopqppCWBMouseStroke`Tu `a_^]\\[\\]^_`aabcdefghiklmnnoooCWBMouseStroked  ( "#%&(*+-/2479<?BEGJMPRUWY[]^^CWBMouseStroke$9 $%%%%%%&&'()*,-/01222332210/-,,,CWBMouseStroke  CWBMouseStroke     CWBMouseStroke H    CWBText__K|eWe know Tan A = 0.75 We know = We seek the value of F where F is the least force"Arial7NG*{osy~CPageCWBMouseStroke*$r0*=bGbGcGcGcGdFdFdFeEfEgDhDjCkBmAo@r?u>x<|:8631.+($!  (4AM[hu{wsssCWBMouseStroke r0 ]fNfNfNfMfMgMgMgMhMhMiMjMjMkMlMnMoMpMrMtMuMwMyM{M~NMMMMMMMMMMMMLLLLLLLLLLLLLKKKKKKK KLLL%L,M4M;MBNJNQOYOaOiOqPyPPPPPQQQQQRRSTVWX#Y,Y,Y,YCWBMouseStroke`Zr0`7%%%%%&&&''(()**+,,-.//011233455667777888888888889999988CWBMouseStroke/)1er0/X^&')+,.1369<?BFIMPTWZ^acfhjl~n}p|q{r{sztzuzvyvywywyxxxxxxxxxxxxxxwxwxwxwxwxwxwxwxwywywzw{w|w}x~xyyyzzz{{||}~CWBMouseStrokeUO6r0UA+88888889::;<>?ACEHJMPSVY\_cfimpswz}CWBMouseStrokeICar0Io?7EEEEEEDDDCBA@?=<:975421/..-,,,--./01345789:;<==>>>>>>>>CWBMouseStrokeYSdr0YH?????????@@@AABBCCCDDDDDDCCCCWBMouseStrokeNH^r0NiM>>>????>>>>>>>>>>>>CWBMouseStrokeuor0 uKabbbbbbbbbbbbbbbbbbaaaaaaaabbbbbbbbcccccccdd d dddddddd d#d%d'd(d*e+e-e.e/d/d0d1d1d1d1d1d1d1d1d0d0d0CWBMouseStroker0 G(^ ^ ^ ] ] ] ] ] ] ]!^"^#^$^%_'_(`*`+a-b.b0c1c2c3d4d4d4e4e3f3g2h0i.j,k*l(m&n$n"n"CWBMouseStroker0 @@AAAAA@@@??? ? ? ? ? ? CWBMouseStroker0 HHHHHHHIIJKLMNNNNMLKJIIIICWBMouseStroker0 TTSSSTTUVWXYZZYXWUTSSSCWBMouseStroke wr0 {%^]]\\[ZZYXWVTSRPOMLJHGECA?=~;{9x7u5r3o2l1i/f/f/fCWBMouseStroke/r0 ,j+k+l*m*o)p)q)q(q(q(q(p)n)l*k*i*g*f+e+e,d,e.e0f2g4g7h:h=g=g=gCWBMouseStroke )r0 RRSTVXZ]adfhjkkkCWBMouseStroke"r0 SQPOOOPQRSTUVWXYZ[\\]^_`abcddddCWBMouseStrokeD>Otr0 D_^^^__``bcegjmptw{CWBMouseStroke3B-<Q\r0 3B!CWBMouseStroke3-_?r0 3,9~|zxvtrpnlkihgffffgijlnpqqrqqpnmkigfffghjlmnooooCWBMouseStroke_Yg/r0 _b __`bdgjmopqppCWBMouseStroke]W w-r0 ]a_^]\\[\\]^_`aabcdefghiklmnnoooCWBMouseStrokelf r0 l ( "#%&(*+-/2479<?BEGJMPRUWY[]^^CWBMouseStroker0 %%%%%%&&'()*,-/01222332210/-,,,CWBMouseStrokeysr0 yCWBMouseStrokesm|r0 s    CWBMouseStrokeyr0 H    CWBText9=9=RpCWe resolve the forces parallel to and perpendicular to the plane "Arial! G,Av0.0